This looks like a shape you might see in actual play. It's similar to the previous pattern, but you should note carefully that the outside liberties of Black's two stones have been filled in. As might be expected, the stones can no longer live unconditionally.
(;AB[qq]AB[pq]AW[oq]AW[nq]AW[pp]AW[qp]AW[qm]C[Black to play and make a ko]AB[lm]AP[goproblems]
(;B[rp];W[ro];B[rr];W[sp];B[sq]
(;W[rq]LB[rp:1]LB[ro:2]LB[rr:3]LB[sp:4]LB[sq:5]LB[rq:6]C[In this shape, playing a hane at 1 and answering White's block at 2 with the open connection of Black 3 is the only possibility. In response to White's atari at 4, Black blocks at 5 and White 6 starts a ko fight.RIGHT])
(;W[so];B[or];W[nr];B[pr];W[rq];B[sr]LB[so:1]LB[or:2]LB[nr:3]LB[pr:4]LB[rq:5]LB[sr:6]C[In the previous diagram, White has no choice but to fight the ko, but let's suppose he connects at 1. What happens? Black can simply hane and connect at 2 and 4. When White captures at 5, Black connects at 6 and has a living shape. Consequently, unless White is totally unable to fight the ko, White 1 is strange.RIGHT]))
(;B[rr];W[rp];B[or];W[nr]
(;B[qs];W[pr];B[os];W[rq]LB[rr:1]LB[rp:2]LB[or:3]LB[nr:4]LB[qs:5]LB[pr:6]LB[os:7]LB[rq:8]C[Lets take a look at Black 1, the move which allowed him to live in the previous pattern. After White 2, Black tries the technique of Black 3 to 5. This time, however, White cuts at 6 and puts the two black stones in atari. Next, after Black 'a' and White 'b', Black is dead.CHOICE])
(;B[ps]LB[sr:a]LB[qr:b]LB[rr:1]LB[rp:2]LB[or:3]LB[nr:4]LB[ps:5]C[After Black 1 and White 2, what about the hand and open connection of Black 3 and 5? If White continues at 'a' and Black connects at 'b', making a ko, then this would also be a possible solution. That is not, however, the way things will proceed. White has the clever attack shown in the next diagram.];W[ns]LB[rr:1]LB[rp:2]LB[or:3]LB[nr:4]LB[ps:5]C[After Black 1 and White 2, what about the hand and open connection of Black 3 and 5? If White continues at 'a' and Black connects at 'b', making a ko, then this would also be a possible solution. That is not, however, the way things will proceed. White has the clever attack shown in the next diagram.]LB[sr:a]LB[qr:b];B[qs];W[rq];B[sr];W[pr]LB[sq:a]LB[rs:b]LB[ns:1]LB[qs:2]LB[rq:3]LB[sr:4]LB[pr:5]C[After the previous diagram, White's descent at 1 is a deadly move. After Black fills his gap at 2, White plays 3 and, in response to Black's descent to 4, throws in at 5, turning the left side into a false eye. If instead of 2, Black plays 3, you shouldverify for yourself that after White 'a', Black 4, and the attachment at White 'b', Black is dead.]))
(;B[or];W[nr]
(;B[ps];W[rq];B[rr];W[qr];B[pr];W[sr]LB[or:1]LB[nr:2]LB[ps:3]LB[rq:4]LB[rr:5]LB[qr:6]LB[pr:7]LB[sr:8]C[What about beginning with the hane and open connection of Black 1 and 3? This, however, is not a very resilient shape. White s hane at 4, cut at 6, and atari at 8 kill Black easily.CHOICE])
(;B[qr]LB[or:1]LB[nr:2]LB[qr:3]C[After Black 1 and White 2, take a look at Black's turn at 3. This is quite a tenacious shape. How should White attack this group? If White had a stone at 'a', then without bothering to make a ko, he would simply capture the black group unconditionally. Lets deal with this in our next problem.CHOICE]LB[lr:a])))